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math on roulette


Jhia

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Posted

i come up with another calculation on stake game, this time where doing roulette, and the chance of winning is just 50% but the thing is you will win on every round that you play once you win , heres the explanation:

 

choose red or black,

and also you always need to know your balance and base bet, most important thing, you should always be able to bet after 10 or 20 lose, in that way theres no way you will end up zero satoshi

then roll. everytime you win you will stay on the base bet, on lose, you need to x2 bet then bet 1 more of your base bet, in that way, if you win you getback waht you lose, plus u win another round,  calculation ffor example is your base bet is 100sat, if you lose you need to double it so it will bw 200sat, then add one more, 

100 sat base bet:

1 bet 100 on lose

2bet 100+100+100 =300sat on lose

3bet double the bet on 2bet means 300x2=600+100=700 on lose

4bet double bet on 3bet 700x2+100=1500 on lose will go on and soforth, until you win 

then if you win go back to 100sat

 

remember you win all round that you play once you win. 

ill edit if if i have another strategy hope this help, 

  • 8 months later...
Posted
49 minutes ago, OsmaNN said:

I only bet on green.

Going green all the time is actually less win rate but you get a 36x multiplier which is one of the things which makes up for it , going red and black gives you a more chance to win. Just a tip :P 

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