Gleidson33 Posted January 13, 2023 #1 Posted January 13, 2023 chance of winning 49.50 initial bet calculate your bet ()x4=()×5=()×7=()×13=()×25=(last bet) . example mine I start initial bet (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×25= (5.62061500) last bet. I put the stop loss after the first sequence of 6 losses because until then he only had 5 consecutive losses. I usually use the busd.
Markosmont33 Posted January 13, 2023 #2 Posted January 13, 2023 3 hours ago, Gleidson33 said: chance of winning 49.50 initial bet calculate your bet ()x4=()×5=()×7=()×13=()×24=(last bet) . example mine I start initial bet (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×24= (5.62061500) last bet. I put the stip loss after the first sequence of 6 losses because until then he only had 5 consecutive losses. I usually use the busd. 3 hours ago, Gleidson33 said: chance of winning 49.50 initial bet calculate your bet ()x4=()×5=()×7=()×13=()×24=(last bet) . example mine I start initial bet (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×24= (5.62061500) last bet. I put the stip loss after the first sequence of 6 losses because until then he only had 5 consecutive losses. I usually use the busd. i tried but i think the initial bet is better a lower multi like 1.25x
Gleidson33 Posted January 14, 2023 Author #4 Posted January 14, 2023 7 hours ago, Ariana said: Gleison33 e possível colocar em português as condições? chance de ganhar 49,50 aposta inicial calcule sua aposta ()x4=()×5=()×7=()×13=()×25=(última aposta) . exemplo meu começo aposta inicial (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×25= (5.62061500) última aposta. Coloquei o stop loss após a primeira sequência de 6 derrotas pois até então ele teve apenas 5 derrotas consecutivas. Eu costumo usar o busd.
Ariana Posted January 15, 2023 #5 Posted January 15, 2023 22 hours ago, Gleidson33 said: chance de ganhar 49,50 aposta cálculo inicial sua aposta ()x4=()×5=()×7=()×13=()×25=(última aposta) . exemplo meu começo aposta inicial (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×25= (5.62061500) aposta última. Coloquei o stop loss após a primeira sequência de 6 derrotas pois então ele teve apenas 5 derrotas consecutivas. Eu costumo usar o busd. Muito obrigadooooo gerson33
Vroli Posted January 17, 2023 #7 Posted January 17, 2023 Excellent! I'll try it in simulation and report back
youcheckibet Posted January 18, 2023 #8 Posted January 18, 2023 On 1/14/2023 at 12:17 AM, Gleidson33 said: chance of winning 49.50 initial bet calculate your bet ()x4=()×5=()×7=()×13=()×25=(last bet) . example mine I start initial bet (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×25= (5.62061500) last bet. I put the stop loss after the first sequence of 6 losses because until then he only had 5 consecutive losses. I usually use the busd. That is quite a lot of stipulations. I will try it out, thank you for sharing.
youcheckibet Posted January 23, 2023 #9 Posted January 23, 2023 On 1/14/2023 at 12:17 AM, Gleidson33 said: chance of winning 49.50 initial bet calculate your bet ()x4=()×5=()×7=()×13=()×25=(last bet) . example mine I start initial bet (0.00012353)×4=(0.00049412)×5= (0.00247060)×7= (0.01729420)×13= (0.22482460)×25= (5.62061500) last bet. I put the stop loss after the first sequence of 6 losses because until then he only had 5 consecutive losses. I usually use the busd. Ok so I ran some samples of 100k bets here and there on this and then I ran the maths. I did profit overall, but long term this is way too risky. On 1c bets your 6 bets are as follows - 1c 4c 20c $1.38 $17.90 $447.61 So you need minimum $467.14 if you are doing 6 bets to sustain 1 loss swing early, but then would need to top up. 0.5 * 0.4 * 0.3 * 0.2 *0.1 * 0.06 if we calculate the loss odd of each occurring it comes out to 0.000072 which means you will see 6 losses hit once every 13,888 bets long term with this strategy. From a tentative sample size around 200k bets total you will see around 8500x profit per 10,000 bets. On 1c this is only $85 and you will hit a $467 loss every 14k bets roughly. Even with playthrough factored, bonuses, RB etc you will get beat up pretty bad. So avoid.
Gleidson33 Posted February 13, 2023 Author #10 Posted February 13, 2023 On 1/23/2023 at 2:19 PM, youcheckibet said: Ok so I ran some samples of 100k bets here and there on this and then I ran the maths. I did profit overall, but long term this is way too risky. On 1c bets your 6 bets are as follows - 1c 4c 20c $1.38 $17.90 $447.61 So you need minimum $467.14 if you are doing 6 bets to sustain 1 loss swing early, but then would need to top up. 0.5 * 0.4 * 0.3 * 0.2 *0.1 * 0.06 if we calculate the loss odd of each occurring it comes out to 0.000072 which means you will see 6 losses hit once every 13,888 bets long term with this strategy. From a tentative sample size around 200k bets total you will see around 8500x profit per 10,000 bets. On 1c this is only $85 and you will hit a $467 loss every 14k bets roughly. Even with playthrough factored, bonuses, RB etc you will get beat up pretty bad. So avoid. Obrigado por isso
youcheckibet Posted February 16, 2023 #12 Posted February 16, 2023 20 hours ago, iboy777 said: Nice strat, will go to try it. Please don't, read my breakdown and I ran about 300k bets on the strategy so I know, there were streaks where I ran good but overall it was a bad loss. It isn't bad for some playthrough, but there are cheaper playthrough ways.
Catsimulator Posted February 17, 2023 #13 Posted February 17, 2023 Man, I've tried like 10 dice strategies, and so far, they all make a little in the beginning then tank you. :c
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